* Step 1: Bounds WORST_CASE(?,O(n^1))
    + Considered Problem:
        - Strict TRS:
            cons(ok(X1),ok(X2)) -> ok(cons(X1,X2))
            dbl(mark(X)) -> mark(dbl(X))
            dbl(ok(X)) -> ok(dbl(X))
            dbl1(mark(X)) -> mark(dbl1(X))
            dbl1(ok(X)) -> ok(dbl1(X))
            dbls(mark(X)) -> mark(dbls(X))
            dbls(ok(X)) -> ok(dbls(X))
            from(ok(X)) -> ok(from(X))
            indx(mark(X1),X2) -> mark(indx(X1,X2))
            indx(ok(X1),ok(X2)) -> ok(indx(X1,X2))
            proper(0()) -> ok(0())
            proper(01()) -> ok(01())
            proper(nil()) -> ok(nil())
            quote(mark(X)) -> mark(quote(X))
            quote(ok(X)) -> ok(quote(X))
            s(ok(X)) -> ok(s(X))
            s1(mark(X)) -> mark(s1(X))
            s1(ok(X)) -> ok(s1(X))
            sel(X1,mark(X2)) -> mark(sel(X1,X2))
            sel(mark(X1),X2) -> mark(sel(X1,X2))
            sel(ok(X1),ok(X2)) -> ok(sel(X1,X2))
            sel1(X1,mark(X2)) -> mark(sel1(X1,X2))
            sel1(mark(X1),X2) -> mark(sel1(X1,X2))
            sel1(ok(X1),ok(X2)) -> ok(sel1(X1,X2))
            top(mark(X)) -> top(proper(X))
            top(ok(X)) -> top(active(X))
        - Signature:
            {cons/2,dbl/1,dbl1/1,dbls/1,from/1,indx/2,proper/1,quote/1,s/1,s1/1,sel/2,sel1/2,top/1} / {0/0,01/0,active/1
            ,mark/1,nil/0,ok/1}
        - Obligation:
            innermost runtime complexity wrt. defined symbols {cons,dbl,dbl1,dbls,from,indx,proper,quote,s,s1,sel,sel1
            ,top} and constructors {0,01,active,mark,nil,ok}
    + Applied Processor:
        Bounds {initialAutomaton = minimal, enrichment = match}
    + Details:
        The problem is match-bounded by 2.
        The enriched problem is compatible with follwoing automaton.
          0_0() -> 2
          0_1() -> 3
          01_0() -> 2
          01_1() -> 3
          active_0(2) -> 2
          active_1(2) -> 5
          active_2(3) -> 6
          cons_0(2,2) -> 1
          cons_1(2,2) -> 3
          dbl_0(2) -> 1
          dbl_1(2) -> 4
          dbl1_0(2) -> 1
          dbl1_1(2) -> 4
          dbls_0(2) -> 1
          dbls_1(2) -> 4
          from_0(2) -> 1
          from_1(2) -> 3
          indx_0(2,2) -> 1
          indx_1(2,2) -> 4
          mark_0(2) -> 2
          mark_1(4) -> 1
          mark_1(4) -> 4
          nil_0() -> 2
          nil_1() -> 3
          ok_0(2) -> 2
          ok_1(3) -> 1
          ok_1(3) -> 3
          ok_1(3) -> 5
          ok_1(4) -> 1
          ok_1(4) -> 4
          proper_0(2) -> 1
          proper_1(2) -> 5
          quote_0(2) -> 1
          quote_1(2) -> 4
          s_0(2) -> 1
          s_1(2) -> 3
          s1_0(2) -> 1
          s1_1(2) -> 4
          sel_0(2,2) -> 1
          sel_1(2,2) -> 4
          sel1_0(2,2) -> 1
          sel1_1(2,2) -> 4
          top_0(2) -> 1
          top_1(5) -> 1
          top_2(6) -> 1
* Step 2: EmptyProcessor WORST_CASE(?,O(1))
    + Considered Problem:
        - Weak TRS:
            cons(ok(X1),ok(X2)) -> ok(cons(X1,X2))
            dbl(mark(X)) -> mark(dbl(X))
            dbl(ok(X)) -> ok(dbl(X))
            dbl1(mark(X)) -> mark(dbl1(X))
            dbl1(ok(X)) -> ok(dbl1(X))
            dbls(mark(X)) -> mark(dbls(X))
            dbls(ok(X)) -> ok(dbls(X))
            from(ok(X)) -> ok(from(X))
            indx(mark(X1),X2) -> mark(indx(X1,X2))
            indx(ok(X1),ok(X2)) -> ok(indx(X1,X2))
            proper(0()) -> ok(0())
            proper(01()) -> ok(01())
            proper(nil()) -> ok(nil())
            quote(mark(X)) -> mark(quote(X))
            quote(ok(X)) -> ok(quote(X))
            s(ok(X)) -> ok(s(X))
            s1(mark(X)) -> mark(s1(X))
            s1(ok(X)) -> ok(s1(X))
            sel(X1,mark(X2)) -> mark(sel(X1,X2))
            sel(mark(X1),X2) -> mark(sel(X1,X2))
            sel(ok(X1),ok(X2)) -> ok(sel(X1,X2))
            sel1(X1,mark(X2)) -> mark(sel1(X1,X2))
            sel1(mark(X1),X2) -> mark(sel1(X1,X2))
            sel1(ok(X1),ok(X2)) -> ok(sel1(X1,X2))
            top(mark(X)) -> top(proper(X))
            top(ok(X)) -> top(active(X))
        - Signature:
            {cons/2,dbl/1,dbl1/1,dbls/1,from/1,indx/2,proper/1,quote/1,s/1,s1/1,sel/2,sel1/2,top/1} / {0/0,01/0,active/1
            ,mark/1,nil/0,ok/1}
        - Obligation:
            innermost runtime complexity wrt. defined symbols {cons,dbl,dbl1,dbls,from,indx,proper,quote,s,s1,sel,sel1
            ,top} and constructors {0,01,active,mark,nil,ok}
    + Applied Processor:
        EmptyProcessor
    + Details:
        The problem is already closed. The intended complexity is O(1).

WORST_CASE(?,O(n^1))